🧠 PKM: K-Way Merge Algorithm (Python)

📌 Context & Core Concept

A K-Way Merge optimizes the combination of K sorted streams (arrays, files, linked lists) into a single unified sorted output. Instead of repeatedly searching all K headers linearly, it utilizes a Min-Heap (Priority Queue) to find the minimum element across streams in O(log⁡K)O(\log K) time.

⏱️ Complexity

  • Time Complexity: O(Nlog⁡K)\mathcal{O}(N \log K) where N is the total number of elements across all lists and K is the number of lists.
  • Space Complexity: O(K)\mathcal{O}(K) auxiliary space to maintain the heap of size K.

🛠️ Python Blueprint (Optimized)

Using Python’s built-in heapq module. To prevent comparison errors when items share the same value, always push a structural tuple containing (value, list_index, element_index) or leverage Python’s heapq.merge generator directly under the hood.

import heapq
from typing import List

def k_way_merge(lists: List[List[int]]) -> List[int]:
    """
    Merges K sorted arrays into one unified sorted array.
    Time: O(N log K) | Space: O(K) 
    """
    min_heap = []
    result = []
    
    # Step 1: Initialize the heap with the first element of each non-empty list
    for list_idx, current_list in enumerate(lists):
        if current_list: # Skip empty lists safely
            # Structure: (value, list_index, element_index)
            heapq.heappush(min_heap, (current_list[0], list_idx, 0))
            
    # Step 2: Extract minimum and replenish from the same list
    while min_heap:
        val, list_idx, elem_idx = heapq.heappop(min_heap)
        result.append(val)
        
        # If the extracted element has a successor in its native list, push it
        if elem_idx + 1 < len(lists[list_idx]):
            next_val = lists[list_idx][elem_idx + 1]
            heapq.heappush(min_heap, (next_val, list_idx, elem_idx + 1))
            
    return result

# --- Verification & Testing ---
if __name__ == "__main__":
    test_input = [[1, 4, 7], [2, 5, 8], [3, 6, 9]]
    output = k_way_merge(test_input)
    print(f"Merged Output: {output}")  # Expected: [1, 2, 3, 4, 5, 6, 7, 8, 9]

⚡ Python Tip: Pro-Level Production Alternate

For pure system implementations where you don’t need customized iteration logic, Python provides an optimized C-level implementation out of the box:

import heapq

# This returns a lazy generator, optimal for external stream files
merged_generator = heapq.merge([1, 4, 7], [2, 5, 8], [3, 6, 9])
result = list(merged_generator)

🚀 High-Yield FAANG Interview Problems

The K-Way Merge is a classic LeetCode pattern. Spotting a collection of pre-sorted lists or a grid with sorted properties (rows/columns) is your primary indicator to use this strategy.

1. Merge k Sorted Lists (LeetCode 23 — Hard)

==Covered here== - merge-k-sorted-lists

  • The Pitch: You are given an array of K linked-lists, each sorted in ascending order. Merge them into one sorted linked list.
  • Why K-Way Merge: This is the most literal application of the pattern. You track the head pointers of all K linked lists in your min-heap.

2. Kth Smallest Element in a Sorted Matrix (LeetCode 378 — Medium)

==👉 covered here== - kth-smallest-element-in-a-sorted-matrix

  • The Pitch: Given an n × n matrix where each of the rows and columns is sorted in ascending order, find the kthk^{th} smallest element.
  • Why K-Way Merge: Treat each row of the matrix as an independent sorted stream. You run the standard K-Way loop exactly k times; the kthk^{th} item you heappop is your direct answer.

3. Find K Pairs with Smallest Sums (LeetCode 373 — Medium)

==Covered here== - find-k-pairs-with-smallest-sums

  • The Pitch: You are given two integer arrays sorted in ascending order, nums1 and nums2. Define a pair (u, v) which consists of one element from the first array and one from the second. Return the K pairs with the smallest sums.
  • Why K-Way Merge: Think of this visually as an implicit grid where row i represents pairing nums1[i] with all items in nums2. Each row is naturally sorted. You run a K-Way merge across these virtual lines.

4. Smallest Range Covering Elements from K Lists (LeetCode 632 — Hard)

==Covered here== - smallest-range-covering-elements-from-k-sorted-lists

  • The Pitch: You have K lists of sorted integers. Find the smallest continuous numerical range that includes at least one number from each of the K lists.
  • Why K-Way Merge: Maintain a min-heap tracking one element from each list. Track the global maximum of the elements currently sitting inside your heap. The difference between your heap’s min (top) and your tracked max forms a viable range. Advance using standard K-Way rules to find the smallest window.

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